Reference to an Array
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/* The following function demostrates the implementations of the "refernce to
an array of one dimension" and the "pointer to an array of 2 dimension"
Reference to an array:
int arr[10] = {1,2,3,4,5,6,7,8,9,0}; // 1 D array of 10 integers
int (&ref_arr)[10] = arr; //reference to an array. Note: array is one dimensional
int arr2D[2][3] = {
1,2,3, //2 D array
3,4,6
};
int (*ptr_arr2D)[3] = arr2D; //Pointer to an array. Note" Array is 2 dimentional
int& Display(int (&rArr)[10], int (*ptrArr)[3]) //function with two parameters
int& (*fptr)(int(&)[10], int (*)[3])= Display; //pointer to a function containing a reference to an array and a pointer to an array and return int reference
*/
#include "stdio.h"
typedef int pointerToArray [16];
int value=100;
int oneD[16];
int& Display(int (&rArr)[10], int (*ptrArr)[3])
{
static int temp[16];
int i=0;
printf("Displaying the one dimentional array: \n");
int count=0, counter=0;
for (count=0; count < 10; ++count)
{
temp[i++]=rArr[count];
printf("%d ", rArr[count]);
}
printf("\n Prining the 2D array\n");
for (count=0; count<2; ++count)
{
for (counter=0; counter<3; ++counter)
{
printf("%d ", ptrArr[count][counter]);
temp[i++]= ptrArr[count][counter]++;
}
printf("\n");
}
// return ptrArr;
return value;
}
void Displayi(int* ptrArr)
{
for (int count=0; count<16; ++count)
{
printf("%d ", ptrArr[count]);
}
}
int main()
{
int arr[10] = {1,2,3,4,5,6,7,8,9,0}; //an array
int (&ref_arr)[10] = arr; //reference to an array. Note: array is one dimensional
int arr2D[2][3] = {
1,2,3,
3,4,6
};
int (*ptr_arr2D)[3] = arr2D; //Pointer to an array. Note" Array is 2 dimentional
int& (*fptr)(int(&)[10], int (*)[3])= Display;
int* array;
fptr(arr, arr2D) = 500;
printf("value = %d\n", value);
// ptr_arr2D= fptr(arr, arr2D);
// Display(array);
}
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